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TIME RATES

Posted by : Allan_Dell on Sunday, September 8, 2013 | 7:55 PM

TIME RATES

Problem:

      1.       A rectangular bin measures 5 meters long and 3 meters wide. How fast will the surface rises if water flows inside rates at 10 ft3/min.

Required:  dh/dt

Solution: 

V = L * W * H

Where:  V = volume
                L = length
               W = width
                H = height

V = LWH (substitute length and width)

V = 5 m * 3 m * H

dv/dt = 30 dH/dt

10 = 30 dH/dt

dH/dt = 0.33 m/min. (answer)


2.       Water from the faucet fills the tank in vertical cylinder in shape at 20 ft3/min in rate. The radius of the tank is 3.5 ft. How fast will the surface of water rises

Required:  dh/dt

Solution: 

V = π * r2 *h

Where:  V = volume
                π = pi
                r = radius
                h = height

V = LWH (substitute the radius)

V = π * r2 *h

V = π * (3.5)2 *h

V = 12.25π h


dV/dt = 12.25 π dh/dt

20 = 12.25 π dh/dt

dh/dt = 20/12.25 * π

dh/dt= 1.632 π ft/min. (answer)


             
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